Files
weave/mesh/routes.go
T
Matthias Radestock 2058ce3f3a refactor: change Routes.RandomNeighbours return for consistency
PeerNameSet -> []PeerName, which is what the other functions
return. This is also easier to deal with at the call site.
2015-11-25 14:46:41 +00:00

277 lines
7.2 KiB
Go

package mesh
import (
"math"
"sync"
)
type unicastRoutes map[PeerName]PeerName
type broadcastRoutes map[PeerName][]PeerName
type Routes struct {
sync.RWMutex
ourself *LocalPeer
peers *Peers
onChange []func()
unicast unicastRoutes
unicastAll unicastRoutes // [1]
broadcast broadcastRoutes
broadcastAll broadcastRoutes // [1]
recalculate chan<- *struct{}
wait chan<- chan struct{}
// [1] based on *all* connections, not just established &
// symmetric ones
}
func NewRoutes(ourself *LocalPeer, peers *Peers) *Routes {
recalculate := make(chan *struct{}, 1)
wait := make(chan chan struct{})
routes := &Routes{
ourself: ourself,
peers: peers,
unicast: make(unicastRoutes),
unicastAll: make(unicastRoutes),
broadcast: make(broadcastRoutes),
broadcastAll: make(broadcastRoutes),
recalculate: recalculate,
wait: wait}
routes.unicast[ourself.Name] = UnknownPeerName
routes.unicastAll[ourself.Name] = UnknownPeerName
routes.broadcast[ourself.Name] = []PeerName{}
routes.broadcastAll[ourself.Name] = []PeerName{}
go routes.run(recalculate, wait)
return routes
}
func (routes *Routes) OnChange(callback func()) {
routes.Lock()
defer routes.Unlock()
routes.onChange = append(routes.onChange, callback)
}
func (routes *Routes) PeerNames() PeerNameSet {
return routes.peers.Names()
}
func (routes *Routes) Unicast(name PeerName) (PeerName, bool) {
routes.RLock()
defer routes.RUnlock()
hop, found := routes.unicast[name]
return hop, found
}
func (routes *Routes) UnicastAll(name PeerName) (PeerName, bool) {
routes.RLock()
defer routes.RUnlock()
hop, found := routes.unicastAll[name]
return hop, found
}
func (routes *Routes) Broadcast(name PeerName) []PeerName {
routes.RLock()
defer routes.RUnlock()
return routes.broadcast[name]
}
func (routes *Routes) BroadcastAll(name PeerName) []PeerName {
routes.RLock()
defer routes.RUnlock()
return routes.broadcastAll[name]
}
// Choose min(log2(n_peers), n_neighbouring_peers) neighbours, with a
// random distribution that is topology-sensitive, favouring
// neighbours at the end of "bottleneck links". We determine the
// latter based on the unicast routing table. If a neighbour appears
// as the value more frequently than others - meaning that we reach a
// higher proportion of peers via that neighbour than other neighbours
// - then it is chosen with a higher probability.
//
// Note that we choose log2(n_peers) *neighbours*, not
// peers. Consequently, on sparsely connected peers this function
// returns a higher proportion of neighbours than elsewhere. In
// extremis, on peers with fewer than log2(n_peers) neighbours, all
// neighbours are returned.
func (routes *Routes) RandomNeighbours(except PeerName) []PeerName {
destinations := make(PeerNameSet)
routes.RLock()
defer routes.RUnlock()
count := int(math.Log2(float64(len(routes.unicastAll))))
// depends on go's random map iteration
for _, dst := range routes.unicastAll {
if dst != UnknownPeerName && dst != except {
destinations[dst] = void
if len(destinations) >= count {
break
}
}
}
res := make([]PeerName, 0, len(destinations))
for dst := range destinations {
res = append(res, dst)
}
return res
}
// Request recalculation of the routing table. This is async but can
// effectively be made synchronous with a subsequent call to
// EnsureRecalculated.
func (routes *Routes) Recalculate() {
// The use of a 1-capacity channel in combination with the
// non-blocking send is an optimisation that results in multiple
// requests being coalesced.
select {
case routes.recalculate <- nil:
default:
}
}
// Wait for any preceding Recalculate requests to be processed.
func (routes *Routes) EnsureRecalculated() {
done := make(chan struct{})
routes.wait <- done
<-done
}
func (routes *Routes) run(recalculate <-chan *struct{}, wait <-chan chan struct{}) {
for {
select {
case <-recalculate:
routes.calculate()
case done := <-wait:
select {
case <-recalculate:
routes.calculate()
default:
}
close(done)
}
}
}
func (routes *Routes) calculate() {
routes.peers.RLock()
routes.ourself.RLock()
var (
oldUnicast = routes.unicast
oldBroadcast = routes.broadcast
unicast = routes.calculateUnicast(true)
unicastAll = routes.calculateUnicast(false)
broadcast = routes.calculateBroadcast(true)
broadcastAll = routes.calculateBroadcast(false)
)
routes.ourself.RUnlock()
routes.peers.RUnlock()
routes.Lock()
routes.unicast = unicast
routes.unicastAll = unicastAll
routes.broadcast = broadcast
routes.broadcastAll = broadcastAll
onChange := routes.onChange
routes.Unlock()
if !unicast.equals(oldUnicast) || !broadcast.equals(oldBroadcast) {
for _, callback := range onChange {
callback()
}
}
}
// Calculate all the routes for the question: if *we* want to send a
// packet to Peer X, what is the next hop?
//
// When we sniff a packet, we determine the destination peer
// ourself. Consequently, we can relay the packet via any
// arbitrary peers - the intermediate peers do not have to have
// any knowledge of the MAC address at all. Thus there's no need
// to exchange knowledge of MAC addresses, nor any constraints on
// the routes that we construct.
func (routes *Routes) calculateUnicast(establishedAndSymmetric bool) unicastRoutes {
_, unicast := routes.ourself.Routes(nil, establishedAndSymmetric)
return unicast
}
// Calculate all the routes for the question: if we receive a
// broadcast originally from Peer X, which peers should we pass the
// frames on to?
//
// When the topology is stable, and thus all peers perform route
// calculations based on the same data, the algorithm ensures that
// broadcasts reach every peer exactly once.
//
// This is largely due to properties of the Peer.Routes algorithm. In
// particular:
//
// ForAll X,Y,Z in Peers.
// X.Routes(Y) <= X.Routes(Z) \/
// X.Routes(Z) <= X.Routes(Y)
// ForAll X,Y,Z in Peers.
// Y =/= Z /\ X.Routes(Y) <= X.Routes(Z) =>
// X.Routes(Y) u [P | Y.HasSymmetricConnectionTo(P)] <= X.Routes(Z)
// where <= is the subset relationship on keys of the returned map.
func (routes *Routes) calculateBroadcast(establishedAndSymmetric bool) broadcastRoutes {
broadcast := make(broadcastRoutes)
for _, peer := range routes.peers.byName {
hops := []PeerName{}
if found, reached := peer.Routes(routes.ourself.Peer, establishedAndSymmetric); found {
routes.ourself.ForEachConnectedPeer(establishedAndSymmetric, reached,
func(remotePeer *Peer) { hops = append(hops, remotePeer.Name) })
}
broadcast[peer.Name] = hops
}
return broadcast
}
func (a unicastRoutes) equals(b unicastRoutes) bool {
for key, aval := range a {
if bval, ok := b[key]; !ok || bval != aval {
return false
}
}
for key := range b {
if _, ok := a[key]; !ok {
return false
}
}
return true
}
func (a broadcastRoutes) equals(b broadcastRoutes) bool {
set := make(map[PeerName]struct{})
for key, aval := range a {
bval, ok := b[key]
if !ok {
return false
}
for _, peer := range aval {
set[peer] = struct{}{}
}
for _, peer := range bval {
if _, ok := set[peer]; !ok {
return false
}
delete(set, peer)
}
if len(set) != 0 {
return false
}
}
for key := range b {
if _, ok := a[key]; !ok {
return false
}
}
return true
}