Matthias Radestock
3cd199e852
The same piece of GossipData can be shared and subject to different Merge operations. We either need to copy the data when we share it, or create copies on modification, i.e. copy-on-write. We choose the latter, since it is more efficient and there is just one mutating operation. Fixes #1697.
46 lines
1.1 KiB
Go
46 lines
1.1 KiB
Go
package mesh
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type SurrogateGossipData struct {
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messages [][]byte
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}
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func NewSurrogateGossipData(msg []byte) *SurrogateGossipData {
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return &SurrogateGossipData{messages: [][]byte{msg}}
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}
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func (d *SurrogateGossipData) Encode() [][]byte {
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return d.messages
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}
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func (d *SurrogateGossipData) Merge(other GossipData) GossipData {
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o := other.(*SurrogateGossipData)
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messages := make([][]byte, 0, len(d.messages)+len(o.messages))
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messages = append(messages, d.messages...)
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messages = append(messages, o.messages...)
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return &SurrogateGossipData{messages: messages}
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}
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// SurrogateGossiper ignores unicasts and relays broadcasts and gossips.
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type SurrogateGossiper struct{}
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func (*SurrogateGossiper) OnGossipUnicast(sender PeerName, msg []byte) error {
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return nil
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}
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func (*SurrogateGossiper) OnGossipBroadcast(_ PeerName, update []byte) (GossipData, error) {
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return NewSurrogateGossipData(update), nil
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}
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func (*SurrogateGossiper) Gossip() GossipData {
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return nil
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}
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func (*SurrogateGossiper) OnGossip(update []byte) (GossipData, error) {
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return NewSurrogateGossipData(update), nil
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}
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var (
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surrogateGossiper SurrogateGossiper
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)
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